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Freezing Point Depression Calculator

Freezing Point Depression Calculator

Calculate freezing point depression and new freezing point using molality and van't Hoff factor

Calculate Freezing Point Depression

mol/kg

Moles of solute per kilogram of solvent

Kf = 1.86 °C·kg/mol, Tf° = 0°C

Freezing Point Depression Results

0.00°C
New Freezing Point
32.0°F
Fahrenheit
273.1K
Kelvin

Formula: ΔTf = i × Kf × m

Calculation: 1 × 1.86 × 0 = 0.00°C

Analysis:

Example Calculation

Antifreeze Solution Example

Problem: Calculate the freezing point of a 0.4 m solution of ethylene glycol in water

Given: Molality (m) = 0.4 mol/kg, Kf for water = 1.86 °C·kg/mol

Solute: Ethylene glycol (C₂H₆O₂) - non-electrolyte, so i = 1

Pure water freezing point: 0°C

Calculation Steps

1. ΔTf = i × Kf × m

2. ΔTf = 1 × 1.86 × 0.4

3. ΔTf = 0.74°C

4. New freezing point = 0°C - 0.74°C = -0.74°C

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Quick Examples

Road Salt (NaCl)

1.0 m NaCl in water

ΔTf ≈ 3.5°C (i = 1.9)

New freezing point: -3.5°C

Sugar Solution

0.5 m sugar in water

ΔTf = 0.93°C (i = 1)

New freezing point: -0.93°C

Calcium Chloride

0.5 m CaCl₂ in water

ΔTf ≈ 2.7°C (i = 2.9)

More effective than NaCl

Common Solvents

Water
Tf° = 0°C
Kf = 1.86
°C·kg/mol
Benzene
Tf° = 5.5°C
Kf = 5.12
°C·kg/mol
Ethanol
Tf° = -114.6°C
Kf = 1.99
°C·kg/mol
Chloroform
Tf° = -63.5°C
Kf = 4.68
°C·kg/mol
Diethyl Ether
Tf° = -116.2°C
Kf = 1.79
°C·kg/mol
Acetone
Tf° = -94.7°C
Kf = 2.4
°C·kg/mol
Phenol
Tf° = 40.9°C
Kf = 7.27
°C·kg/mol

van't Hoff Factors

Sugar (C₁₂H₂₂O₁₁)
Non-electrolyte
i = 1
Ethylene Glycol (C₂H₆O₂)
Non-electrolyte
i = 1
Sodium Chloride (NaCl)
Strong electrolyte
i = 1.9
Calcium Chloride (CaCl₂)
Strong electrolyte
i = 2.9
Potassium Nitrate (KNO₃)
Strong electrolyte
i = 1.9
Magnesium Sulfate (MgSO₄)
Strong electrolyte
i = 1.3
Aluminum Chloride (AlCl₃)
Strong electrolyte
i = 3.2
Urea (CO(NH₂)₂)
Non-electrolyte
i = 1

Understanding Freezing Point Depression

What is Freezing Point Depression?

Freezing point depression is a colligative property that occurs when a nonvolatile solute is added to a pure solvent. The freezing point of the solution becomes lower than that of the pure solvent. This phenomenon is directly related to the concentration of solute particles in the solution.

Key Concepts

  • Colligative property - depends on particle concentration, not identity
  • Greater molality = greater freezing point depression
  • Electrolytes produce more particles than non-electrolytes
  • Each solvent has a unique cryoscopic constant (Kf)

Formula and Calculations

Basic Formula

ΔTf = i × Kf × m

ΔTf = freezing point depression (°C)

i = van't Hoff factor (particles per formula unit)

Kf = cryoscopic constant (°C·kg/mol)

m = molality (mol solute/kg solvent)

New Freezing Point

Tf(solution) = Tf°(pure) - ΔTf

The solution always freezes at a lower temperature

van't Hoff Factor

Non-electrolytes: i = 1

Strong electrolytes: i = number of ions

Actual values are often less than theoretical

Real-World Applications

Road De-icing

Salt (NaCl) and calcium chloride (CaCl₂) are spread on roads to lower the freezing point of water, preventing ice formation.

Antifreeze

Ethylene glycol in car radiators prevents coolant from freezing in winter temperatures.

Food Science

Sugar and salt in ice cream prevent it from freezing solid, maintaining a scoopable texture.

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