Natural Frequency Calculator

Calculate natural frequencies for springs, beams, cantilevers, and structural systems

System Configuration

Spring-Mass System: Mass connected to a spring with elastic constant k

Formula: f = (1/2π) × √(k/M)

System Parameters

N/m

Output Units

Natural Frequency Results

Enter system parameters to calculate natural frequency
Provide all required parameters for the selected system type

Example Calculation

Spring-Mass System

Given: Spring constant k = 100 N/m, Mass M = 2 kg

Angular frequency: ω = √(k/M) = √(100/2) = 7.07 rad/s

Natural frequency: f = ω/(2π) = 7.07/(2π) = 1.125 Hz

Period: T = 1/f = 0.889 s

Simply Supported Beam

Given: Steel beam, L = 10 m, E = 200 GPa, I = 2.14×10⁻⁵ m⁴, M = 500 kg

f = (1/2π) × √(48EI/(ML³))

f = (1/2π) × √(48×200×10⁹×2.14×10⁻⁵/(500×10³)) = 3.04 Hz

System Types

Spring-Mass
Simple oscillator
f = (1/2π)√(k/M)
Supported Beam
Two-end support
f = (1/2π)√(48EI/ML³)
Cantilever
Fixed-free beam
f = (1/2π)√(3EI/FL³)

Typical Elastic Moduli

Steel200 GPa
Aluminum70 GPa
Concrete30 GPa
Wood12 GPa
Brass100 GPa

Frequency Ranges

Human Activity0.5-5 Hz
Machinery5-20 Hz
Equipment20-100 Hz
High Frequency>100 Hz

Vibration Tips

Natural frequency is intrinsic property

Avoid resonance for structural safety

Higher stiffness = higher frequency

Higher mass = lower frequency

Period = 1/frequency

Understanding Natural Frequency

What is Natural Frequency?

Natural frequency is the frequency at which a system oscillates when not subjected to a continuous or repeated external force. Every object has at least one natural frequency, and some complex objects have multiple natural frequencies. When an external force matches the natural frequency, resonance occurs, which can lead to dramatic amplitude increases.

vs. Resonant Frequency

  • Natural Frequency: Frequency of free vibration (no external force)
  • Resonant Frequency: Frequency at which maximum response occurs under forced vibration
  • Relationship: Nearly identical in lightly damped systems

System Formulas

Spring-Mass System

f = (1/2π) × √(k/M)

ω = √(k/M)

k = spring constant, M = mass

Supported Beam

f = (1/2π) × √(48EI/(ML³))

E = elastic modulus, I = moment of inertia, L = length

Cantilever Beam

f = (1/2π) × √(3EI/(FL³))

F = force at free end

Engineering Applications

Structural Design

Avoid resonance with operational frequencies (machinery, wind, seismic)

Vibration Control

Design dampers and isolators based on natural frequencies

Modal Analysis

Identify critical modes and frequencies for complex structures

Design Considerations

Avoid Resonance

Keep natural frequency away from excitation frequencies

Stiffness vs. Mass

Increase stiffness or reduce mass to raise natural frequency

Damping

Add damping to reduce resonance amplification