Projectile Motion Calculator

Analyze parabolic motion, trajectory, range, and flight time

Calculate Projectile Motion

m/s

Speed at which projectile is launched

°

Angle above horizontal (45° = optimal range)

m

Height above ground at launch (0 = ground level)

Projectile Motion Results

2.88
Time of Flight (s)
40.77
Range (m)
10.19
Max Height (m)
1.44
Time to Max Height (s)

Initial Velocity Components

Horizontal (vₓ):14.14 m/s
Vertical (vᵧ):14.14 m/s

Position at t = 1.4s

Horizontal (x):20.39 m
Vertical (y):10.19 m
Velocity:14.14 m/s

Physics Formulas Used

Velocity Components: vₓ = v₀cos(α), vᵧ = v₀sin(α)

Position: x = vₓt, y = h + vᵧt - ½gt²

Time of Flight: t = (vᵧ + √(vᵧ² + 2gh))/g

Range: R = vₓ × t

Max Height: h_max = h + vᵧ²/(2g)

Physics Analysis

✅ Optimal angle for maximum range (45°)
🎯 Trajectory follows a parabolic path due to constant horizontal velocity and gravity acceleration

Example: Basketball Free Throw

Problem Setup

Scenario: Basketball player shoots from free-throw line

Given: v₀ = 8 m/s, α = 45°, h = 2 m (release height)

Question: Will the ball reach the basket 4.6 m away?

Solution Steps

1. Calculate velocity components: vₓ = 8×cos(45°) = 5.66 m/s, vᵧ = 8×sin(45°) = 5.66 m/s

2. Find time of flight: t = (5.66 + √(5.66² + 2×9.81×2))/9.81 = 1.36 s

3. Calculate range: R = 5.66 × 1.36 = 7.7 m

4. Compare: 7.7 m > 4.6 m - Ball overshoots the basket!

Result: Need lower angle or less velocity for accurate shot

Real-World Examples

Basketball Shot

Free throw trajectory

Velocity: 8 m/s
Angle: 45°
Height: 2 m

Cannonball

Historical artillery

Velocity: 50 m/s
Angle: 30°
Height: 5 m

Soccer Ball Kick

Goal attempt

Velocity: 25 m/s
Angle: 25°
Height: 0 m

Arrow Shot

Archery target practice

Velocity: 60 m/s
Angle: 15°
Height: 1.5 m

Key Physics Concepts

P

Parabolic Trajectory

Curved path due to gravity

V

Velocity Components

Horizontal and vertical motion

G

Gravity Effect

Constant downward acceleration

R

Range Optimization

45° gives maximum range

Essential Formulas

Velocity Components

vₓ = v₀cos(α)

vᵧ = v₀sin(α)

Position Equations

x = vₓt

y = h + vᵧt - ½gt²

Range (Ground Level)

R = v₀²sin(2α)/g

Maximum at α = 45°

Maximum Height

h_max = h + v₀²sin²(α)/(2g)

Height above launch point

Understanding Projectile Motion

What is Projectile Motion?

Projectile motion describes the path of an object launched into the air, subject only to gravity. The trajectory forms a parabola due to the constant horizontal velocity and accelerating vertical motion.

Key Principles

Horizontal and vertical motions are independent. Horizontal velocity remains constant (no air resistance), while vertical motion follows free-fall physics with gravity acceleration of 9.81 m/s².

Optimal Launch Angle

For maximum range on level ground, the optimal launch angle is 45°. This balances horizontal distance with flight time. Different angles optimize for specific scenarios.

Real-World Applications

Sports (basketball, soccer, archery), military ballistics, space launches, and engineering design all use projectile motion principles for trajectory prediction and optimization.

Sports Applications

  • • Basketball shooting angles
  • • Soccer ball trajectories
  • • Golf ball flight paths
  • • Baseball pitching physics

Engineering Uses

  • • Spacecraft launch trajectories
  • • Artillery range calculations
  • • Water fountain design
  • • Safety equipment testing

Physics Education

  • • Vector analysis
  • • Kinematic equations
  • • Energy conservation
  • • Motion independence principle