Birthday Paradox Calculator

Calculate the probability of at least two people sharing a birthday in a group

Birthday Paradox Calculator

Enter the size of the group (1-400 people)

Choose whether to include leap years in calculations

Birthday Paradox Results

50.73%
Probability of Shared Birthday
253
Possible Pairs
6.12%
Probability for Specific Date
22
Days with at Least One Birthday

Formula: P(at least one match) = 1 - P(no matches)

P(no matches): (365/365) × (364/365) × ... × ((365-n+1)/365)

Days in year: 365 days

Probability Analysis

🎯 High probability - more likely than not to have shared birthdays.

Famous Examples

The Classic Example

23 people: 50.73% probability

30 people: 70.63% probability

50 people: 97.04% probability

70 people: 99.92% probability

Real-World Applications

• Cryptography (birthday attack)

• Hash collision detection

• Quality control sampling

• Network protocol analysis

Quick Reference

10 people11.69%
20 people41.14%
23 people50.73%
30 people70.63%
50 people97.04%
70 people99.92%

Key Insights

Only 23 people needed for 50% probability

70 people gives 99.9% probability

Probability grows exponentially

Based on comparing all possible pairs

Understanding the Birthday Paradox

What is the Birthday Paradox?

The birthday paradox is a famous probability problem that demonstrates how our intuition about probability can be misleading. It asks: what's the probability that at least two people in a group share the same birthday?

Why is it Surprising?

  • Only 23 people needed for 50% probability
  • Much fewer than the 183 people you might expect
  • Growth is exponential, not linear
  • Number of pairs grows as n(n-1)/2

The Mathematics

P(no match) = (365/365) × (364/365) × ... × ((365-n+1)/365)

P(match) = 1 - P(no match)

Why It Works

  • 1st person: Any birthday (365/365 = 100%)
  • 2nd person: Must avoid 1st (364/365 ≈ 99.7%)
  • 3rd person: Must avoid first 2 (363/365 ≈ 99.5%)
  • And so on... Probabilities multiply

Key insight: We're not looking for a specific match, but any match among all possible pairs!